|\frac{x^2-x-2}{x^4+10x^2+9}| \leq \frac{|x^2-x-2|}{|x^4+10x^2+9|}\leq \frac{|x^2|+|x|+2}{|x^4+10x^2|-9}\leq \frac{R^2+R+2}{R^4-10R^2-9}