=\displaystyle\lim_{x\to 0} \frac{(1 + x^{2} ) \cdot (e^{1.5x^2} - 1)+x^2}{\frac{ \sin2x }{2x}\cdot 2x^2 }=\displaystyle\frac{:x^2}{:x^2}= \displaystyle\lim_{x\to 0} \frac{(1 + x^{2} ) \cdot \frac{e^{1.5x^2} - 1}{1.5 x^2}\cdot 1.5+ 1}{2\cdot\frac{ \sin2x }{2x}}=