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$\begin{equation} \begin{aligned} (E'A')^{\tau} &= ((M^{\tau}M)(M^{-1}AM))^{\tau} = (M^{\tau}AM)^{\tau} \\ &= M^{\tau}A^{\tau}(M^{\tau})^{\tau} = M^{\tau}AM = M^{\tau}M(M^{-1}AM) \\ &= E'A' \end{aligned} \end{equation}$
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