T_{2k-1} := \left\{ \displaystyle\frac{(-1)^{2k-1} + 2(2k-1)}{(2k-1) \sin\left( \frac{(-1)^{(2k-1) - 1}\pi}{2} \right)} : k \in \mathbb{N} \right\} = \left\{ 2 - \displaystyle\frac{1}{2k-1} : k \in \mathbb{N}\right\}