x^2 - \frac{\pi }
{2}\int_0^1 {x^2 \sin \left( {\pi x} \right)dx} - \frac{{x - \frac{1}
{2}}}
{{\frac{1}
{{2\pi }} - \frac{4}
{{\pi ^3 }}}}\int_0^1 {\left( {x - \frac{1}
{2}} \right)x^2 \sin \left( {\pi x} \right)dx}