This is LaTeX code:

[latex]
a_n=\dfrac{\sqrt{n^2+1}-n}{\sqrt{n+3}+2n}>\dfrac{\sqrt{n^2+1}-n}{\sqrt{n+4}+2n+2}>\dfrac{\sqrt{(n+1)^2+1}-(n+1)}{\sqrt{n+4}+2n+2}=a_{n+1}
[/latex]