\begin{array}{l}
 y: = \frac{2}{3} + \frac{{11}}{5} \Rightarrow 3y = 3 \cdot \left( {\frac{2}{3} + \frac{{11}}{5}} \right) = 3 \cdot \frac{2}{3} + 3 \cdot \frac{{11}}{5} = \\ 
 = 2 + 3 \cdot \frac{{11}}{5} \Rightarrow 5 \cdot \left( {3y} \right) = 5 \cdot 2 + 5 \cdot \left( {3 \cdot \frac{{11}}{5}} \right) = \\ 
 = 10 + 3 \cdot \left( {5 \cdot \frac{{11}}{5}} \right) = 10 + 3 \cdot 11 = 10 + 33 = 43 \Rightarrow \\ 
 \Rightarrow 15y = 43 \\ 
 \end{array}