y' = \left(\frac{\sqrt{f(x)}}{g(x)}\right)' = \frac{\left(\sqrt{f(x)}\right)' g(x) - \sqrt{f(x)}g'(x)}{g(x)^2} = \frac{\frac{f'(x)}{2\sqrt{f(x)}} g(x) - \sqrt{f(x)}g'(x)}{g(x)^2}