P(\frac{1}{X-2}\leq 1)=P(X \in (-\infty,2)U[3,\infty))=1-P(2\leq X<3) = 1 - \int_{2}^{3} \frac{1}{2\sqrt{2\pi}}e^{\frac{-(x-3)^2}{8}}dx=...=1-\int_{0}^{1/2} \varphi(t)dt=1-0.1915=0.8085