G:=\lim_{x \rightarrow 0}\Big[-\frac{1}{x^2}\ln(1+x)+ \frac{1}{x}\cdot \frac{1}{1+x}\Big]=\lim_{x \rightarrow 0}\frac{-\frac{1}{x}\ln(1+x)+ \cdot \frac{1}{1+x}}{x}