This is LaTeX code:

[latex]
a_{n+1} = \frac{2}{3}a_n - 4 \Rightarrow
a_{n+1} - a_n = -\frac{1}{3}a_n - 4 \leq \frac{1}{3}(12) - 4 = 4 - 4 = 0
[/latex]